The
vibrating system and its characteristics can be represented by an electric
circuit. Now let’s consider the electrical circuit which is shown in the next
figure.
The
system consists of inductor L, a resistor R and a capacitor C. When the voltage
E(t) is applied to the system, it caused a current of magnitude i to flow
through the circuit. As the current flows past the inductor the voltage drop is
L(di/dt). When the current flows through the resistor the voltage drop is Ri,
and when it arrives at the capacitor the drop is
$$\frac{1}{C}\int{idt}$$
Since
the current cannot flow past a capacitor, it’s only possible to measure the
charge q acting on the capacitor. The charge can be related to the current by
the equation
$$i=\frac{dq}{dt}$$
Thus
the voltage drops, which occur across the inductor, resistor, and capacitor
becomes
$$L\frac{{{d}^{2}}q}{d{{t}^{2}}},R\frac{dq}{dt},\frac{q}{C}$$
By
applying the Kirchhoff’s law which states that the applied voltage balances the
sum of the voltage drops around the circuit. Therefore:
$$L\frac{{{d}^{2}}q}{d{{t}^{2}}}+R\frac{dq}{dt}+\frac{1}{C}q=E(t)$$
As
you can see the previous differential equation which represents the change of
voltage in electrical system is similar to the differential equation which
describes the motion of Viscous Dampers Forced Vibration system.
By
comparing these to differential equation we can see that these equation have
the same form, and hence mathematically the procedure of analyzing an electric
circuit is the same as that of analyzing a vibration mechanical system
$$m\frac{{{d}^{2}}x}{d{{t}^{2}}}+c\frac{dx}{dt}+kx=F(t)$$
From
this we can derive the analogs between two equations and we will show them in
the following table.
Electrical
|
Mechanical
|
||
Electric Charge
|
q
|
Displacement
|
x
|
Electric Current
|
i
|
Velocity
|
dx/dt
|
Voltage
|
E(t)
|
Applied Force
|
F(t)
|
Inductance
|
L
|
Mass
|
m
|
Resistance
|
R
|
Viscous damping coefficient
|
c
|
Reciprocal of capacitance
|
1/C
|
Spring stiffness
|
k
|
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